t^2-8td-20d^2=

Solution for t^2-8td-20d^2= equation:

Simplifying
t2 + -8td + -20d2 = 0

Reorder the terms:
-8dt + -20d2 + t2 = 0

Solving
-8dt + -20d2 + t2 = 0

Solving for variable 'd'.

Factor a trinomial.
(-2d + -1t)(10d + -1t) = 0

Subproblem 1
Set the factor '(-2d + -1t)' equal to zero and attempt to solve:

Simplifying
-2d + -1t = 0

Solving
-2d + -1t = 0

Move all terms containing d to the left, all other terms to the right.

Add 't' to each side of the equation.
-2d + -1t + t = 0 + t

Combine like terms: -1t + t = 0
-2d + 0 = 0 + t
-2d = 0 + t
Remove the zero:
-2d = t

Divide each side by '-2'.
d = -0.5t

Simplifying
d = -0.5t
Subproblem 2
Set the factor '(10d + -1t)' equal to zero and attempt to solve:

Simplifying
10d + -1t = 0

Solving
10d + -1t = 0

Move all terms containing d to the left, all other terms to the right.

Add 't' to each side of the equation.
10d + -1t + t = 0 + t

Combine like terms: -1t + t = 0
10d + 0 = 0 + t
10d = 0 + t
Remove the zero:
10d = t

Divide each side by '10'.
d = 0.1t

Simplifying
d = 0.1t
Solution
d = {-0.5t, 0.1t}